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SAT(R) Math Cheat Sheet

Numbers & Arithmetic

Percents

To get the percent of a value:

Sd=FS*d=F

where SS is the starting amount, dd is the percent expressed as a decimal, and FF is the final result.

To calculate a percentage increase or decrease:

Sm=FS*m=F

where SS is the starting amount, mm is the percent change expressed as a multiplier, and FF is the final result.

To convert a percentage change into a multiplier:

% ChangeCalculationMultiplier
formulap%p\%1+p1001+\frac{p}{100}mm
increase12%12\%1+121001+\frac{12}{100}1.121.12
increase35%35\%1+351001+\frac{35}{100}1.351.35
increase150%150\%1+1501001+\frac{150}{100}2.52.5
increase0.5%0.5\%1+0.51001+\frac{0.5}{100}1.0051.005
decrease12%-12\%1121001-\frac{12}{100}0.880.88
decrease40%-40\%1401001-\frac{40}{100}0.600.60

To convert a multiplier into a percentage change:

MultiplierCalculation% Change
formulamm(m1)100(m-1)*100p%p\%
increase1.121.12(1.121)100(1.12-1)*100+12%+12\%
increase1.351.35(1.351)100(1.35-1)*100+35%+35\%
increase2.52.5(2.51)100(2.5-1)*100+150%+150\%
increase1.0051.005(1.0051)100(1.005-1)*100+0.5%+0.5\%
decrease0.880.88(0.881)100(0.88-1)*10012%-12\%
decrease0.60.6(0.61)100(0.6-1)*10040%-40\%

Fractions

Cross multiplication:

ab=cd\frac{a}{b} = \frac{c}{d} ad=caa*d=c*a

Dividing by a fraction:

abcd=abdc\frac{\frac{a}{b}}{\frac{c}{d}}= \frac{a}{b}*\frac{d}{c}

Linear Functions

Slope formula

Given two points, (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2), the slope of a linear equation is:

m=y2y1x2x1 m=\frac{y_2-y_1}{x_2-x_1}

Slope-intercept Form

Given an equation in the form y=mx+cy=mx+c:

  • the slope of the line is mm
  • the slope of the perpendicular line is 1/m-1/m
  • the yy-intercept is cc
  • the xx-intercept is c/m-c/m

Standard Form

Given an equation in the form ax+by=kax+by=k:

  • the yy-intercept is k/bk/b
  • the xx-intercept is k/ak/a
  • the slope of the line is a/b-a/b
  • the slope of the perpendicular line is b/ab/a

Quadratic Functions

General Form

Given a quadratic function in the form f(x)=ax2+bx+cf(x)=ax^2+bx+c:

  • the axis of symmetry is at x=b/2ax=-b/2a
  • the vertex is at (b/2a,f(b/2a))(-b/2a, f(-b/2a))
  • the sum of the solutions is b/a-b/a
  • the product of the solutions is c/ac/a
  • the solutions, if they exist, are
x=b±b24ac2ax=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}
  • To determine how many solutions a quadratic has:

b24ac>0\sqrt{b^{2}-4ac} > 0 => Two solutions

b24ac=0\sqrt{b^{2}-4ac} = 0 => One solution

b24ac<0\sqrt{b^{2}-4ac} < 0 => No solutions

  • To determine the distance between the solutions:
b24aca\frac{\sqrt{b^{2}-4ac}}{a}

xx-intercept Form

Given a quadratic function in the form f(x)=a(xp)(xq)f(x)=a(x-p)(x-q):

  • the solutions are x={p,q}x=\{p, q\}
  • the axis of symmetry is p+q2\frac{p+q}{2}
  • the coordinates of the vertex are (p+q2,f(p+q2))(\frac{p+q}{2}, f(\frac{p+q}{2}))
  • the product of solutions is pqpq
  • the sum of solutions is p+qp+q

Vertex Form

Given a quadratic function in the form f(x)=a(xh)2+kf(x)=a(x-h)^2+k:

  • the coordinates of the vertex are (h,k)(h, k)
  • the axis of symmetry is hh
  • the solutions, if they exist, are x=h±ka x=h\pm\sqrt{-\frac{k}{a}}\
  • if k=0k=0, the quadratic has 1 solution
  • if k/a>0-k/a > 0, then the quadratic has two solutions
  • if k/a<0-k/a < 0, then the quadratic has no solutions
  • the product of solutions is h2+kah^{2}+\frac{k}{a}
  • the sum of solutions is 2h2h
  • the distance between the solutions is 2ka2\sqrt{-\frac{k}{a}}

Exponential Functions

Given an exponential function in the form f(x)=abkx+df\left(x\right)=ab^{kx}+d:

  • the yy-intercept is a+da+d
  • the growth rate is bb, expressed as a multiplier
    • if 0<b<10 < b < 1, then the function is decreasing.
    • if b>1b > 1, then the function is increasing.
  • kk is how many times the function ff increases or decreases per step in the xx.

Stats & Probability

Mean

  • the mean is the simple or weighted average of a set of numbers:
xˉ=xff\bar{x} = \frac{\sum{xf}}{\sum{f}}

Where xx is the value of each item and ff is the amount of times the item appears (the frequency).

For example, if A={1,2,2,2,3,5,5,7}A = \{1, 2, 2, 2, 3, 5, 5, 7\}, then the mean is:

xˉ=11+32+13+25+178 \bar{x}=\frac{1*1+3*2+1*3+2*5+1*7}{8}

Mode

Given a set of numbers, the mode is the number that appears most frequently:

For example, if A={1,2,2,2,3,5,5,7}A = \{1, 2, 2, 2, 3, 5, 5, 7\}, then the mode of set AA is 22.

Median

Given a set of ordered numbers, the median is the middle number:

For example, if A={1,2,2,2,3,5,5,7}A = \{1, 2, 2, 2, 3, 5, 5, 7\}, then the median of set AA is 2.52.5.

Standard Deviation

Given a set of numbers, the standard deviation tells us how spread out the data are. For example, for these two data sets:

A={10,12,12,12,13,15,15,17}A = \{10, 12, 12, 12, 13, 15, 15, 17\}

B={1,5,7,12,13,18,22,27}B = \{1, 5, 7, 12, 13, 18, 22, 27\}

Both are more or less centered around 1212 but set BB has a larger standard deviation because the numbers are more spread out.

You shouldn't ever need to calculate the standard deviation, but you should be able to tell whether one data set has a higher standard deviation than the other.

Geometry & Trigonometry

SOHCAHTOA

SOHCAHTOA is pretty much all you need on the SAT for trig problems.

Effect of method efficiency on final score

From these relationships, we can also determine that:

sin(x)=cos(90x)sin(x)=cos(90-x)

which is equivalent to:

x+y=90sin(x)=cos(y)x+y=90 sin(x)=cos(y)

30-60-90 Triangle

Any triangle whose angles are 30°, 60°, and 90° will have side lengths in the following ratios:

shortest sidemiddle sidehypotenuse
general casexxx3x\sqrt{3}2x2x
example 122232\sqrt{3}44
example 2733\frac{7\sqrt{3}}{3}771433\frac{14\sqrt{3}}{3}

45-45-90 Triangle

Any triangle whose angles are 45°, 45°, and 90° will have side lengths in the following ratios:

shortest sidehypotenuse
general casexxx2x\sqrt{2}
example 155525\sqrt{2}
example 2722\frac{7\sqrt{2}}{2}77

Pythagorean Triples

Any triangle whose side lengths are in the following ratios will be right angled triangles:

side Aside Bside Cnote
345super common
51213uncommon
81517super rare

Circle Arcs and Sectors

Given a slice of a circle, like so:

Effect of method efficiency on final score

We can say that:

arc2πr=sectorπr2=θ°360°=θ rads2π\frac{arc}{2\pi{r}} = \frac{sector}{\pi{r^2}} = \frac{\theta°}{360°} = \frac{\theta{\ rads}}{2\pi}